Question
Draw the circuit
of Half-wave rectifier and its output waveform. A diode whose -internal
resistance is 20 Ω is to supply
power to 1000 Ω load from 110
V (RMS) source. Calculate (a peak load current, (b) DC load current, (c)
AC load current.
Peak load current Imax = Vmax / (r+R) = 110√2/(20+1000) =
152.5 mA
DC curent Idc
= Imax /π = 152.5
/ π mA =
48.5 mA
AC curent = Imax / 2 = 152.5 / 2
= 76025mA